Question

for which angle of projection the range and its maximum height will be equal?​

Answer 1

$\huge\purple{\boxed{\mathscr{✮Answer࿐}}}$

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In projectile thrown at angle θ Range R and maximum height H are given as :

Range, $R=\frac{u^2(sin2θ)}{g}=\frac{u^22sinθcosθ}{g}$

Maximum Height, $H=\frac{u^2sin^2θ}{2g}$

Given: $H=R$

⇒ $\frac{u^2(2sinθcosθ)}{g}=\frac{u^2sin^2θ}{2g}$

⇒ 4cosθ = sinθ

⇒ tanθ =4

⇒ θ = 76°

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Hope it Helps !!!!