Question

For which condition the quadratic equation (a2 + b2 )x2-2(ac+bd)x+(c+d)=0 has equal roots.

Answer 1

Answer:

Step-by-step explanation:

If given equation has equal roots

Discriminant=0

[-2{ac+bd}]^2=4(a^2+b^2)(c^2+d^2)

4{a^2c^2+b^2d^2+2acbd}=4{a^2c^2+a^2d^2+b^2c^2+b^2d^2}

a^2c^2+b^2d^2+2abcd=a^2c^2+a^2d^2+b^2c^2+b^2d^2

(ac-bd)^2=0

ac=bd

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