Math, asked by alonsoevans2, 1 year ago

For which equations is x = 9 a possible solution? Check all that apply. |x| = 9 –|x| = 9 –|–x| = 9 –|–x| = –9 |x| = –9 |–x| = 9 |–x| = –9

Answers

Answered by kitt3ns4life08
2

Answer:

The answers are A, D, and F.

(x) = 9

-(-x) = 9

(-x) = 9

Step-by-step explanation:

Answered by bandameedipravalika0
0

Answer:

Concept :

Mod or modules of x are terms used to describe |x|. These vertical bars | | are used to indicate the absolute value, or to put it another way, the variable or constant represented by the bars always has a value that is greater than 0, or positive. LET'S look at an illustration Let x=-4. Consequently, |x|=|-4|=4|X|= 4

Step-by-step explanation:

  • The answer to the question is x=9. Everything is good. You search for potential positive ones using this information.
  • We can also remove the slashes to read the words regularly.
  • Therefore, the first one has x = 9 and is a keep, while -x = 9 has a negative x and is not it.
  • If you recall the laws of positives and negatives, x = 9 will appear because two negatives equal a positive. That is a hold.
  • The fourth has three drawbacks. Because there isn't another negative, the first to make the x positive reads as x = -9.
  • A no-keeper Due to the -9, the fifth isn't the case. Due to the -x, it is not the sixth.
  • The seventh is a bit unclear to me because the negatives can be crossed out to make them both positive, but at the same time, it can also be interpreted as -x=-9 on its own.

#SPJ2

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