for which integer n^2+19n+90 is Perfect square
Answers
Answered by
2
-10 and -9
hope it may help you...
hope it may help you...
Attachments:
Answered by
0
n^2+(10+9)n+ 90=0
n^2+10n+9n+ 90=0
n(n+10)+9(n+10)=0
therefore, =-10 and '-9
for the values n=-10,-9 the integer n^2+19n+90 is a perfect square
n^2+10n+9n+ 90=0
n(n+10)+9(n+10)=0
therefore, =-10 and '-9
for the values n=-10,-9 the integer n^2+19n+90 is a perfect square
Similar questions