For which of the following angles of projection, the projectite will NOT have the same range? A) 75 15⁰ (B) 30, 60° (C) 60°, 15 (D) 40, 50°
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Answer:
Explanation:
Correct option is
C
100 m
The horizontal range of a projectile fixed at an angle=15°
Range=50m
In dirst case range=50=u
2
/g(sin2×15°)
50=
2g
2
g
u
2
=100
In 2nd case range=
g(sin2×45°)
u
2
=
1
100
(∵sin90°=1)
=100m
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