For which of the following, is g(x)
1
g(x)=
(x2 + 5x – 6)(x2 – 3x – 28
defined ?
a)
x = 7
b)
x = 6
c)
X = 1
d) x = -4
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Step-by-step explanation:
option B. x=6
substitute 7 in x place
g(x)=1/((7)*+5(7)-6).((7)*-3(7)-28)
g(x)=1/(49+35-6).(49-21-28)
g(x)=1/78(0)
g(x)=not defined
substitute 6 in x place
g(x)=1/((6)*+5(6)-6).((6)*-3(6)-28)
g(x)=1/(36+30-6).(36-18-28)
g(x)=1/(60).(-10)
g(x)=1/-600
g(x)= -1/600
substitute 1 in x place
=1/(1+5-6).(1-3-28)
=1/(0).(-30)
=not defined
substitute -4 in x place
=1/(16-20-6).(16+12-28)
=1/(-10).(0)
=not defined
So,6 is defined in g(x)
Hope this helps you
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