Question

For which of the following values of x and y do the following equations 3x+y=19 and x-y=9 satisfy

Answer 1

Answer:

$x - y = 9 = > 3(x - y) = 3 \times 9 = > 3x - 3y = 27$

$3x + y = 19$

$3x + y - (3x - 3y) = 19 - 27 = > 3x + y - 3x + 3y = - 8 = > 4y = - 8 = > y = - 2$

Now,

$x - y = 9 = > x - ( - 2) = 9 = > x + 2 = 9 = > x = 7$

So, x = 7 and y = -2

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Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

x - y = 9 = > 3(x - y) = 3 \times 9 = > 3x - 3y = 27x−y=9=>3(x−y)=3×9=>3x−3y=27

3x + y = 193x+y=19

3x + y - (3x - 3y) = 19 - 27 = > 3x + y - 3x + 3y = - 8 = > 4y = - 8 = > y = - 23x+y−(3x−3y)=19−27=>3x+y−3x+3y=−8=>4y=−8=>y=−2

Now,

x - y = 9 = > x - ( - 2) = 9 = > x + 2 = 9 = > x = 7x−y=9=>x−(−2)=9=>x+2=9=>x=7

So, x = 7 and y = -2