Question

For which salt are there EQUAL numbers of electrons with respect to the anion, and the cation?

Answer 1

answer is rubidian bromide.

explanation:

And so we gots

Na+Cl-

−

, i.e. 10 electrons associated with the

Na+cation, and 18 electrons associated with the

Cl+anion.

And for

Li+F−

, i.e. 2 electrons associated with the

Li+cation, and 10 electrons associated with the

Cl−anion.

And for

K+Br−

, i.e. 18 electrons associated with the

K+cation, and 36 electrons associated with the

Br−anion.

And for

Rb+Br−

, i.e. 36 electrons associated with the

Rb+cation, and 36 electrons associated with the

Br-anion.