Question

for which system does the equilibrium constant Kc has units of (concentration)​

Answer 1

Answer:

for 2nd system

Explanation:

concentration is inverse in Kc units of second order reaction.

hope it helps

pls mark as brainliest

Answer 2

Answer:

The equilibrium constant Kc has the units of (concentration)⁻¹ for reaction:- 2NO₂   ⇄   N₂O₄

Therefore, the option (3) is correct.

Explanation:

The units of equilibrium constant will depend on the number of moles of reactants as well as the moles of products. When the number of moles of reactants is equal to the total number of moles of products, then equilibrium constant will have no units.

(1.) Formation of ammonia:-

N₂   +   3H₂   ⇄    2NH₃

The equilibrium constant is ratio of concentration of products to the concentration of reactants.

$K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}=\frac{C^3}{C.C^3} =\frac{C^2}{C^4}$

$K_c=\frac{1}{C^2}$

Therefore the equilibrium constant will have units of (concentration)⁻² for this reaction.

(2.) Formation of HI:-

H₂   +   I₂   ⇄    2HI

Here, C represent the unit of concentration such as molL⁻¹.

$K_c=\frac{[HI]^2}{[H_2][I_2]}=\frac{C^2}{C.C} =\frac{C^2}{C^2}$

Therefore, the equilibrium constant has no units.

(3.) Formation of N₂O₄:-

2NO₂   ⇄   N₂O₄

The equilibrium constant will be:-

$K_c=\frac{[N_2O_4]}{[NO_2]^2}=\frac{C}{C^2}$

$K_c=\frac{1}{C}$

Therefore, for this reaction the equilibrium constant will have unit (concentration)⁻¹.

(4.) Decomposition of HF:-

    2HF   ⇄   H₂   +   F₂  

The equilibrium constant is given by:-

$K_c=\frac{[H_2][F_2]}{[HF]^2}=\frac{C.C}{C^2} =\frac{C^2}{C^2}$

Therefore the equilibrium constant of this reaction has no units.

To learn more about "equilibrium constant "

https://brainly.in/question/8460195

To learn more about "Units of equilibrium constant"

https://brainly.in/question/12852620