Question

for which value of an acute angleA then cosA/1-sinA + cosA/1+sinA = 4​

Answer 1

Step-by-step explanation:

secA = 2

consider L. H. S cos A/1-sin A + cosA/1+sin A

Take cos A as common, we get

cos A (1/1-sin A + 1/1+sinA)

= cos A [1+sinA+1-sinA] /(1-sin A) (1+sinA)

=cos A(2/1-sin2 A)

=cos A (2/cos2 A)

=2/cos A

=2 sec A

2 sec A= 4

then,

implies, sec A= 2

RHS = 4