For which value of k does the pair of equation given below has unique solution ?
2kx + 3y + 3 = 0
4x + y + 4 = 0
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Answer:
If the equation has unique solution then,
a1/a2 is not = b1/b2
Here, a1=2k b1=3
a2=4 b2=1
So, 2k/4 is not = 3/1
2k is not equal to 12
k not equal to 6.
k can be any integer except 6.
Hope you find this helpful
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