Question

For which value of K, the equation 2x2+Kx+3=0 has equal roots?​

Answer 1

Answer:

D = b^2-4ac

so

We have

a=2

b=k ,c=3

D=0

k^2 - 4*2*3=0

k^2=24

k=√2

thanks

Answer 2

$\huge{\boxed{\textsf{\textbf{\color{lime}{Question:-}}}}}$

For which value of k, the equation 2x² + kx + 3 = 0

has equal roots ?

$\huge{\boxed{\textsf{\textbf{\color{lime}{Answer:-}}}}}$

2x² + Kx + 3 = 0

On comparing with ax²+bx+c = 0,

a = 2

b = k

c = 3

Since, the equation has two equal roots,

D = 0

b² - 4ac = 0

Put the values in b² - 4ac :

( k )² - 4 ( 2 ) ( 3 ) = 0

k² - 24 = 0

k = ±√24

k = $±\sqrt{6×4}$

k = $±2\sqrt{6}$

Therefore, for k = $±2\sqrt{6}$, the equation 2x² + Kx + 3 = 0 has equal roots.

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Hope it helps :)

This is the right solution ✌️