For which value of K, the equation 2x2+Kx+3=0 has equal roots?
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Answered by
13
Answer:
∴ for k = ±216 given equation has equal roots.
Step-by-step explanation:
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Answered by
1
Answer:
k = 2 ROOT 6
Step-by-step explanation:
2x² + kx + 3 = 0
On comparing with ax² + bx + c = 0
a = 2 , b = k , c = 3
D = ROOT b² - 4ac
For equal value D = 0
D = ROOT k² - 4 × 2 × 3
0 = ROOT k² - 24
k = ROOT 24
k = 2 ROOT 6
Hope it helps you....
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