for which value of k the equation have on solution 3 X + Y= 1
( 2 k - 1 ) X + (K - 1) Y =2 k + 1
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Answer:3x +y = 1
Subtract 1 both side we get
3x + y – 1 = 0
(2k –1) x + (k –1) y = 2k + 1
Subtract 2k +1 both side we get
(2k –1) x + (k –1) y – (2k + 1)= 0
3x+y=1 and
(2k-1)x+(k-1)y=2k+1
They can be rewrite as:
3x + y - 1 = 0 and
(2k-1)x + (k-1)y - (2k+1) = 0
Compare with
We get
And for no solution
Take
Cross multiply we get
3k - 3 = 2k - 1
k = 3-1
k = 2
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