Question

for which value of k the pair of equarions kx+3y =k-3 and 12x +ky =k has no solutuion.

Answer 1

If  a1 /  a2 ≠  b1 /  b2 then the pair of linear equations a1x + b1y + c1 = 0 a2x+ b2y + c2 = 0  has a unique solution. Given pair of  equations K x + 3y = K-3, 12x + Ky = K. Here a1 = k ,b1 = 3 , a2 = 12 , b2 = k . k / 12 ≠ 3 / k k2 ≠ 36. k ≠ ± 6.

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