Question

For which value of k the pair of linear equations have infinite solutions x+y=2 , 3x+3y=k

Answer 1

Answer:

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Step-by-step explanation:

so here given linear equations are

x+y=2 , 3x+3y=k

comparing them with a1x+b1y=c1 and a2y+b2y=c2

respectively

we get

a1=1,b1=1,c1=2

a2=3,b2=3,c2=k

since above linear equations have infinitely many solutions

we can conclude that

a1/a2=b1/b2=c1/c2

ie 1/3=1/3=2/k

so considering 1/3=2/k

ie k=3×2

so k=6

thus value of k is 6