Question

For which value of k the quadratic equation kx2

-3x+k = 0 has real and equal roots?​

Answer 1

Step-by-step explanation:

For roots to be equal discriminant should be equal to 0

${b}^{2} - 4ac = 0$

${( - 3)}^{2} - 4(k)(k) = 0$

$9 - 4 {k}^{2} = 0$

$\frac{9}{4} = {k}^{2}$

Taking square root on both sides

$k = + - \frac{3}{2}$