For which value of k the quadratic equation kx2
-3x+k = 0 has real and equal roots?
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Answered by
0
Answer:
Answer
For the equation kx
2
+x+k=0 to have equal zeros the discriminant must be zero.
Hence, 1−4k
2 =0
=>k 2 = 4
∴k=± 2/1
Answered by
2
Answer:
If a equation has equal and real roots,
discriminant D shold be 0.
b²-4ac=0
in this equation kx²-3x+k=0
a=k; b=-3; c=k
b²-4ac = 0
=(-3)²- 4×k×k=0
=9-4k² =0
-4k² = -9
4k² = 9
k² = 9/4
k = √9 / √4
k =3/2
therefore value of k is 3/2 for the given condition.
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