Question

for which value of k the quadratic equation kx²-3x +k =0 has real and equal root​

Answer 1

Step-by-step explanation:

Here, we have kx

2

+1=kx+3×−11k

2

(k+11)x

2

−(k+3)x+1=0

a=k+11

⇒b=−(k+3)=c=1

Since, given equation has real & equal roots, so D = 0

b

2

−4ac=0

(−k−3)

2

−4(k+11)(1)=0

k

2

+2k−35=0

⇒(k+7)(k−5)=0

k=−7,5.

Answer 2

Answer:

Since the roots are real and equal, ∴ D = b

2 − 4ac = 0

⇒k

2 – 4×3×3 = 0 (∵ a = 3, b = k, c = 3)

⇒k

2 = 36

⇒k = 6 or −6