Question

for which value of K will the following pair of linear equation have no solution?

3x+y=1
(2k-1)x+(k-1)y=2k+1

Answer 1

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Answer 2

$\huge {\bold {\pink {Heya}}}$

3x+y=1 and

(2k-1)x+(k-1)y=2k+1

They can be rewrite as:

3x + y - 1 = 0 and

(2k-1)x + (k-1)y - (2k+1) = 0 

 

 We know that, for the given system to have no solution,=≠

⇒  

⇒ 3k - 3 = 2k - 1

⇒ k = 3-1

⇒ k = 2

Hence, for k = 2, the given system of equation will have no solution.