Question

For which value of k will the following pair of linear equations have no solution? 3x + y = 1(2k — 1) x+ (k — 1) y = 2t + 1


K = 5

K = 3

K = 2

K = 6

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Answer 1

Answer:

correct option is (C) k= 2

Step-by-step explanation:

we have

3x+y=1

(2k-1)x + (k-1)y =2k+1

and the condition of no solution is

a1/a2=b1/b2≠c1/c2

3/(2k-1)=1/(k-1)≠q/(2k+1)

3/(2k-1)=1/(k-1)

3(k-1)= 1(2k-1)

3k-3=2k-1

3k-2k= -1+3

k=2 ans.

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