for which value of k will the following system of linear equations have unique solution x+2y=5;3x+ky+15=0
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x+2y=5
Taking x=1 & y=2
Subtitute the values
1+2×2=5
Giving these values in 2nd equation
3×1+k×2+15=0
3+2k+15=0
2k+18=0
2k= -18
K =-9
Taking x=1 & y=2
Subtitute the values
1+2×2=5
Giving these values in 2nd equation
3×1+k×2+15=0
3+2k+15=0
2k+18=0
2k= -18
K =-9
priyanshi8736:
not correct!
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