Question

for which value of k will the pair of equation kx+3y=k-3 and 12x+ky=k have no solution

Answer 1

kx+3y−(k−3)=0;12x+ky−k=0kx+3y−(k−3)=0;12x+ky−k=0For infinitely many no. of solution;a1a2=b1b2=c1c2a1a2=b1b2=c1c2k12=3k=k−3kk12=3k=k−3kk12=3k⟹k2=36k12=3k⟹k2=36∴k=±6