Question

for which value of p does e^n/(1+e^9n)^4p converges​

Answer 1

${\huge{\bold{\underline{Answer:-}}}}$

$f(x)=lnpxx→f′(x)=p(lnx)p−1−lnpxx2=(lnx)p−1x2⋅(p−lnx)<0⟺p<lnx⟺ep<x. This shows that starting at some index n>ep, the series converges conditionally for all p's.$