Question

for which value of p does the pair of equation has unique solution 4x+py+8=0and2x+2y+2=0​

Answer 1

Answer:

p≠4

Explanation:

Compare 4x+py+8=0,

2x+2y+2 =0 with

a1x+b1y+c1 = 0 and

a2x+b2y+c2=0,we get

a1=4, b1=p , c1 = 8;

a2 = 2 , b2 = 2 , c2 = 2

Now ,

a1/a2 ≠ b1/b2

[ Given , unique solution ]

=> 4/2 ≠ p/2

=> (4×2)/2 ≠ p

=> 4 ≠ p

Therefore,

p≠ 4

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