Question

for which value of Y for the distance of two point P(2,-3) and Q(10,Y) is 10 units​

Answer 1

Answer: Y=+3 or, Y=-9

Step-by-step explanation:

Distance between two given points=$\sqrt{(Y+3)^{2} +(10-2)^{2} }$=10

or, $(Y+3)^{2}+8^{2} =10^{2}$

or, $(Y+3)^2}=100-64$=$36=6^{2}$

or, Y+3=+-6

if (Y+3)=+6, Y=+3

and if (Y+3)=-6, Y=-9

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