Question

For which value(s) of k will the pair of equations
kx + 3y = k - 3
12x+ky = k
have no solution?​

Answer 1

Answer:

For no solution --

a1/a2 = b1 / b2 ≠ c1/c2

k/12 = 3/k ≠ (k -3)/ k

k^2 = 36 ≠ (k-3)/k

k = +-6