for which value s of k will the pair of linear equations Kx + 3y -(k -3)= 0 and 12 + ky -k. = 0 have infinite number of solutions.
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for value s of k will the pair of linear equations Kx + 3y -(k -3)= 0 and 12 + ky -k. = 0 have infinite number of solutions.
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for which value s of k will the pair of linear equations Kx + 3y -(k -3)= 0 and 12 + ky -k. = 0 have infinite number of solutions.Step-by-step explanation:
The work done is negative.(-25N)
W= WORK DONE
F = FORCE ACTING ON THE OBJECT
S = DISTANCE/DISPLACEMENT/HEIGHT
W = F * S (For positive work) Equation 1
W = - F * S (For negative work) Equation 2
HERE, we will use Equation 2
Substituting all the values, we get
W =-F * S
W = -5 * 5
W = - 25 N
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