For which values of a and b, are the zeroes of q(x) = x3+ 2x2 + a also the zeroes
of the polynomial p(x) = x5 - x4- 4x3 + 3x² + 3x + b? Which zeroes of p(x) are
not the zeroes of q(x)?
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Step-by-step explanation:
for zeroes of q(x) be also the zeroes of p(x), then q(x) should be the factor of p(x)
that is q(x) should wholly divide p(x) {with remainder 0}
p(x) = x⁵ - x⁴ -4x³ +3x² + 3x + b
q(x) = x³ +2x² +a
p(x) = q(x) . (x² -3x + 2) + x²(-1-a) +x(3+3a) + b-2a
now remainder to be zero implies
coefficient of x² = 0 ⇒ a = -1
coefficient of x = 0 ⇒ 3a = -3 ⇒ a = -1
and b-2a = 0 ⇒ b = -2
therefore p(x) = x⁵ - x⁴ -4x³ + 3x² - 2
and q(x) = x³+2x²-1
other zeroes of p(x) ; solving (x² -3x +2 )=0
x = 1 and x= 2
hope this helps
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