Question

For which values of k does the pair of equations given below has unique solution 2x+3y-5=0 and kx-6y-8=0

Answer 1

Answer:

unique solution = a1/a2 not equal to b1/b2.

a1=2, a2=k and b1=3, b2= -6

•°• 2/k not equal to 3/-6

then we have to cross multiply it we get

3k not equal to -12

k is not equal to -12/3

k is not equal to -4

henve k can have any values rather than -4.