Question

For which values of k does the pair of equations have no solutions ? 2x(a-b)y2b+1 4x-(a-1)=5b-1 by elimination method

Answer 1

The given equations are:

2x-(a-4)y=2b+1 and 4x-(a-1)y=5b-1

Therefore, a_{1}=2, a_{2}=4,b_{1}=-(a-4), b_{2}=-(a-1), c_{1}=2b+1, c_{2}=5b-1

Since, it is given that the system of linear equations have infinite many solutions, therefore

\frac{a_{1}}{a_{2}}= \frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\frac{2}{4}=\frac{-(a-4)}{-(a-1)}=\frac{2b+1}{5b-1}

\frac{a-4}{a-1}=\frac{2}{4}, \frac{2b+1}{5b-1}=\frac{2}{4}

2a-8=a-1, 4b+2=5b-1

a=7 and b=3 IS YOUR ANSWER