Question

For which values of p does the following equation has equal roots?

2x2

-px+8=0
​

Answer 1

Step-by-step explanation:

From the given equation,

a=2, b=p+1, c=8

If an equation has real and equal roots, then ,

b^2 - 4ac = 0

Substituting,

(p+1) ^2 -4(2)(8) = 0

p^2+ 2p+ 1-64 = 0

p ^2b + 2p - 63 = 0

Solving for p,

p = −2 ± 4 - 4 . (-63) / 2

p = 7 and p = - 9