Question

For which values of p does the following equation has equal roots?

2x²-Px+8=0​

Answer 1

Answer:

Answer. The quadratic formula says x = (-p +/- sqrt(p^2 - 4 * 2 * 8)) / (2*2). This yields nonreal solutions when p^2 - 4 * 2 * 8 < 0, real solutions otherwise. Thus, if the equation is to have real solutions, p^2 - 4 * 2 * 8 >= 0, or p^2 >= 64, or p >= 8.0