Math, asked by hasnainmansuri1860, 3 months ago

For which values of p does the following equation has equal roots?

2x2

-px+8=0​

Answers

Answered by muskanperween225
0

Step-by-step explanation:

The given quadratic equation is 2x^2 - px + 8 = 0

From equation we get, a = 2 , b = -p and c = 8.

The roots are real and equal.

 {b}^{2}  - 4ac = 0

( { - p)}^{2}  - 4 \times 2 \times 8 = 0

 {p}^{2}  - 64 = 0

 {p}^{2}  = 64

p =  \sqrt{64}

p = 8

The value of p is 8.

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