Question

For which values of p does the following equation has equal roots?

2x2

-px+8=0​

Answer 1

Step-by-step explanation:

The given quadratic equation is 2x^2 - px + 8 = 0

From equation we get, a = 2 , b = -p and c = 8.

The roots are real and equal.

${b}^{2} - 4ac = 0$

$( { - p)}^{2} - 4 \times 2 \times 8 = 0$

${p}^{2} - 64 = 0$

${p}^{2} = 64$

$p = \sqrt{64}$

$p = 8$

The value of p is 8.