Question

For which values of p does the following equation has equal roots?

2x2
-px+8=0


please guys help me and solve my question​

Answer 1

Refer the attachment and see the answer

Answer 2

SOLUTION

TO DETERMINE

The value of p such that the quadratic equation

$\sf{2 {x}^{2} - px + 8 = 0}$

has equal roots

EVALUATION

Here the given Quadratic equation is

$\sf{2 {x}^{2} - px + 8 = 0}$

Since the two roots are equal

∴ Discriminant = 0

$\sf{ \implies \: {( - p)}^{2} - 4 \times 2 \times 8 = 0 }$

$\sf{ \implies \: {p}^{2} - 64 =0 }$

$\sf{ \implies \: {p}^{2} = 64 }$

$\sf{ \implies \: p = \pm \: 8 }$

Hence the required value of p is + 8 or - 8

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. On a coordinate grid, the location of a bank is (–4, 8) and the location of a post office is (2, 0). The scale used is

https://brainly.in/question/23019403

2. A line L passes through P(1, 2) such that P bisects the line segment intercepted between the axes, then the Perpendicular

https://brainly.in/question/27338264