Question

For which values of p does the following equation has equal roots?
2x
2
-px+8=0 ​

Answer 1

Answer:

For which values of p does the following equation has equal roots?

2x

2

-px+8=0

Answer 2

Answer: p=8

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Step-by-step explanation:

For roots to be equal the discriminant should be equal to zero

D=$\sqrt{b^{2}-4ac }$

now equation is 2x^2-px+8=0

Discriminant:

$\sqrt{p^{2}-4(2)(8) } =0\\p^{2}-64=0\\p^{2}=64\\p=\sqrt{64\\}\\p=8$

hope it helps