For which values of p does the following equation has
equal boots ? 2x²-P x + 8 = 0
Answers
Answered by
0
Step-by-step explanation:
D = b2-4ac
a=2, b=-p, c=8
p2-4(2)(8)=0
p2=64
p=8
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Answered by
13
Given : A quadratic equation 2x² - px + 8 = 0
To Find : Value of x
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As we know that :
If the roots are equal then ,
D (discrminant) = 0
Formula for finding D (discrminant) :
Here
- a = 2
- b = p
- c = 8
Put the values and solve !!
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