Question

for which values(s) of k will the following equations has no solution

kx + 3y=k-3
12x + ky = k

Answer 1

Answer:

Heya !!!

KX + 3Y = K -3

KX + 3Y - ( K -3) = 0 ------------(1)

And,

12X + KY = K

12X + KY - K = 0

These equations are of the form of A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0

Where,

A1 = K , B1 = 3 and C1 = -K +3

And,

A2 = 12 , B2 = K and C2 = -K

For no solution we must have,

A1/A2 = B1/B2 # C1/C2 [ Where # stand for not equal]

K / 12 = 3/K

K² = 12 × 3

K² = 36

K = ✓36 = 6

★ HOPE IT WILL HELP YOU ★

Answer 2

Answer:

Step-by-step explanation:

A set of linear equations have no solution when the ratio of corresponding x and y terms of both equations are equal

Suppose equations

a x + b y =c

a2 x + b2 y = c2

then a/a2 = b/b2

Therefore

k/12 = 3/k

k  = 6