Question

for x=1/10,y=-3/5,z=7/20, find the value of the expression s (x-y) -z and x- (y-z). are they equal​

Answer 1

Answer:

$\left(\frac{1}{10}-\left(-\frac{3}{5}\right)\right)-\frac{7}{20}=\frac{1}{10}-\left(-\frac{3}{5}-\frac{7}{20}\right)\quad :\quad \mathrm{False}$

Step-by-step explanation:

$\left(\frac{1}{10}-\left(-\frac{3}{5}\right)\right)-\frac{7}{20}=\frac{1}{10}-\left(-\frac{3}{5}-\frac{7}{20}\right)$

$\left(\frac{1}{10}-\left(-\frac{3}{5}\right)\right)-\frac{7}{20}$

Remove parentheses: (a)=a, −(−a)=a

$=\frac{1}{10}+\frac{3}{5}-\frac{7}{20}$

$10,\:5,\:20$

$\mathrm{Compute\:a\:number\:comprised\:of\:factors\:that\:appear\:in\:at\:least\:one\:of\:the\:following:}$

$10,\:5,\:20$

$=2\cdot \:2\cdot \:5$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:5=20$

$=\frac{2}{20}+\frac{12}{20}-\frac{7}{20}$

Since the denominators are equal, combine the fractions: a c ± b c = a± b c

$=\frac{2+12-7}{20}$

$\mathrm{Add/Subtract\:the\:numbers:}\:2+12-7=7$

$=\frac{7}{20}$

$\frac{7}{20}=\frac{21}{20}$

$\mathrm{The\:sides\:are\:not\:equal}$

Answer 2

Answer:

I am a boy

Step-by-step explanation:

thanks for answering