Question

for x=1/10,y= -3/5 ,z=7/20, find the values of the expressions (x-y)-z and x-(y-z) are they equal​ ?

Answer 1

Answer:

$(x - y) - z = ( \frac{1}{10} - ( - \frac{3}{5} )) - \frac{7}{20} \\ = ( \frac{1}{10} + \frac{3}{5} )- \frac{7}{20} \\ = ( \frac{1}{10} + \frac{6}{10} )- \frac{7}{20} \\ = \frac{7}{10} - \frac{7}{20} \: \\ = \frac{14}{20} - \frac{7}{20} \\ = \frac{7}{20} \\ (x - y) - z = \: \frac{7}{20} \: ........(1) \\ \\ x -( y- z) = \frac{1}{10} - ( - \frac{3}{5} - \frac{7}{20} ) \\ = \frac{1}{10} - ( - \frac{12}{20} - \frac{7}{20} ) \\ = \frac{1}{10} - ( - \frac{19}{20} ) \\ = \frac{1}{10} + \frac{19}{20} \\ = \frac{2}{20} + \frac{19}{20} \\ = \frac{21}{20} \\ thus \\ x -( y- z) = \: \frac{21}{20} \: ........(2) \\ hence \: from \: (1) \: and \: (2) \: it \: is \: \\ clear \: that \\ \: (x - y) - z \neq \: x -( y- z) \:$

Answer 2

Answer:

(x-y)-z ≠ x-(y-z)

Step-by-step explanation:

here we have given the values :

x = 1/10

y = -3/5

z = 7/20

putting the values in equation :

(x-y)-z and x-(y-z)

= (1/10 - (-3/5)) ≠ 1/10 - (-3/5 - 7/20)

Solution :

⇒ (1/10 - (-3/5)) ≠ 1/10 - (-3/5 - 7/20)

⇒ (1 -(-6))/10 - 7/20 ≠ 1/10 - (-12-7)

⇒  7/10 - 7/20 ≠ 1/10 - (-19/20)

⇒  14-7/20 ≠ 2-(-19)

⇒  7/20 ≠ 21/20