Question

For x = 1/3 and y = 3/5
verify that - (x + y) = (-x) +(-y)​

Answer 1

Question:

For x = 1/3 and y = 3/5 verify that

- (x + y) = (-x) +(-y)

Solution:

$\tt { x = \frac {1}{3} }$

$\tt {y = \frac {3}{5} }$

Putting the values of x and y in -(x +y) = (-x)+ (-y)

$\tt {- ( x + y) = ( -x) + (-y) }$

$: \implies \tt {( -x - y )= (-x - y)}$

$: \implies \tt {\frac{-1}{3} - \frac{3}{5}= \frac{-1}{3} - \frac{3}{5}}$

$: \implies \tt {\frac{-8}{15} = \frac{-8}{15} }$

Hence, verified.

Answer 2

GiveN:

• $\sf x = \frac{1}{3}$
• $\sf y = \frac{3}{5}$

To FinD:

(x + y) = (-x) +(-y)

SolutioN:

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(x + y) = (-x) +(-y)

$: \implies-( \frac{1}{3} + \frac{3}{5} ) = ( - \frac{1}{3} ) + ( - \frac{3}{5} )$

$: \implies - ( \frac{5 + 9}{15} ) = \frac{ - 5 - 9}{15}$

$: \implies \frac{ - 14}{15} = \frac{ - 14}{15}$

LHS = RHS

hence, verified ✔

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