Question

For x = 2, y = 3, u = -2 and v = -3, point (x + y, u + v) lies in the __________ quadrant.

Answer 1

Answer:

(x+y,u+v)=(2+3,-2+(-3))=(5,-5)

(5,-5) lies in 4th quadrant

Answer 2

For x = 2, y = 3, u = - 2, v = - 3 the point (x + y, u + v) lies in the IV quadrant

Given :

x = 2, y = 3, u = - 2, v = - 3

To find :

For x = 2, y = 3, u = - 2, v = - 3 the point (x + y, u + v) lies in the _______ quadrant

Concept :

We know that in two dimensional geometry the Cartesian plane is divided by coordinate axis in 4 quadrant

1. Quadrant I : Both the x - coordinates and y - coordinates are positive

2. Quadrant II : The x - coordinate is negative and the y - coordinate is positive

3. Quadrant III : Both the x - coordinates and y - coordinates are negative

4. Quadrant IV : The x - coordinate is positive and the y - coordinate is negative

Solution :

Step 1 of 2 :

Find the point

Here it is given that x = 2, y = 3, u = - 2, v = - 3

Now the point (x + y, u + v)

= ( 3 + 2 , - 2 - 3 )

= ( 5 , - 5 )

Step 2 of 2 :

Find the quadrant where the point lies

For the point (5, - 5)

x - coordinates = Abscissa = 5 which is positive

y - coordinate = Ordinate = - 5 which is negative

So the point lies on IV Quadrant

Hence for x = 2, y = 3, u = - 2, v = - 3 the point (x + y, u + v) lies in the IV quadrant

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ locate the following points on the cartesian plane(aEr) (0,a),(a,0),(-a, 0),(0,-a)...

https://brainly.in/question/26822338

2. Distance of a point A(-2,0) from x-axis is _______ units.

https://brainly.in/question/28760447