Question

For x = 3, y = 2, u = -9, v = 13 the point (x + y, u + v) lies in the _______ quadrant.(a) III
(b) II
(c) IV
(d) I

Answer 1

Answer: 1st we solve:-

(x+y )= 3+2=5

(u+v)=(-9)+13=4

So,(5,4) lies in 1st quandrat

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Step-by-step explanation:

Answer 2

For x = 3, y = 2, u = -9, v = 13 the point (x + y, u + v) lies in the I quadrant

Given :

x = 3 , y = 2 , u = - 9 , v = 13

To find :

For x = 3, y = 2, u = -9, v = 13 the point (x + y, u + v) lies in the _______ quadrant

(a) III

(b) II

(c) IV

(d) I

Concept :

We know that in two dimensional geometry the Cartesian plane is divided by coordinate axis in 4 quadrant

1. Quadrant I : Both the x - coordinates and y - coordinates are positive

2. Quadrant II : The x - coordinate is negative and the y - coordinate is positive

3. Quadrant III : Both the x - coordinates and y - coordinates are negative

4. Quadrant IV : The x - coordinate is positive and the y - coordinate is negative

Solution :

Step 1 of 2 :

Find the point

Here it is given that x = 3, y = 2, u = - 9, v = 13

Now the point (x + y, u + v)

= ( 3 + 2 , - 9 + 13 )

= ( 5 , 4 )

Step 2 of 2 :

Find the quadrant where the point lies

For the point (5,4)

x - coordinates = Abscissa = 5 which is positive

y - coordinate = Ordinate = 4 which is positive

So the point lies on Quadrant I

Hence the correct option is (d) I

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