Question

For x² ≠ (nπ + 1), n ∈ N (the set of natural numbers), the integral ∫ x. √[{2sin(x² - 1) - sin2(x² - 1)}÷{2sin(x² - 1) + sin2(x² - 1)}] dx is :
(A) logₑ |(1/2)sec²(x² - 1)| + c
(B) (1/2)logₑ |sec²(x² - 1)| + c
(C) (1/2)logₑ |sec²(x² - 1)/2| + c
(D) logₑ |sec²(x² - 1)/2| + c
[JEE Main 2019]

Answer 1

Answer:

Step-by-step explanation:

The answer for this question is:

HCF = 1

LCM = 1680