Question

FORCE = 20 N, mass of object = 3 kg , accleration is 0.5 m/s2 what is magnitude if frictional force? plzzz explain with formula

Answer 1

generally we Know, frictional force = coefficient of friction × normal reaction between surface and body .

but we also Know, friction force oppose the relative motion of body .

here , force( F) = 20N
let f is the frictional force appear due to motion of body with respect to floor .

now,

F -f = ma

20 - f = 3× 0.5

f = 20 -1.5 = 18.5 N

Answer 2

Answer:

Explanation:

generally we Know, frictional force = coefficient of friction × normal reaction between surface and body .

but we also Know, friction force oppose the relative motion of body .

here , force( F) = 20N

let f is the frictional force appear due to motion of body with respect to floor .

now,

F -f = ma

20 - f = 3× 0.5

f = 20 -1.5 = 18.5 N