Question

Force 5√2 N and 6√2 N are acting on a body of mass 1000 kg at an angle to 60° to each other. Find acceleration, distance covered and velocity of mass after 10s. ​

Answer 1

Answer:

Resultant force=( 6√2)² +(5√2)²+2*6√2*5√2*cos60=182N

F=M×A

A=F/M

A=182÷1000

=0.182m/s²

now,

V=U+A×T

V=0+0.182×10

V=1.82m/s

V=DISPLACEMENT/TIME

D=V×T

D=1.82×10

D=18.2m