Question

Force 6N (j) acts on a particle with position vector r= 3.0m(i). What is the torque on
the particle about the origin, in unit-vector notation?

Answer 1

Answer:

${ \sqrt{y43)x \frac{632 \times \frac{?}{?} }{?} } }^{2} \times \frac{?}{?}$

Answer 2

Answer:

6n + 200

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