Question

Force acting on a block moving along x-axis is given by F = - ((4)/(x^(2)+2))N The block is displaced from x = - 2m to x = + 4m, the work done will be

Answer 1

Explanation:

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Force at x=-2

Now ,

F=-4/ (-2)²+2

F=-4/4+2

F=-4/6

F=-⅔

Force at x=4

Now,

F=-4/(4)²+2

F=-4/16+2

F=-4/18

F=-2/9

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@ Twilight Astro ✌️☺️❤️

Answer 2

Answer:

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FORCE X = -2

$f \: = ( - 4) \div ( - 2) {}^{2} + 2 \\ f \: = - 4 \div 6 \\ f = ( - 2) \div 3$

FORCE X = 4

$f \: = ( - 4) \div 4 {}^{2} + 2 \\ f \: = ( - 4) \div 18 \\ f \: = ( - 2) \div 9$

HOPE THAT HELPS