Question

force acting on a body of mass 10 kg if the velocity of of the body changes from 5 m s -1 to 3 m s -1 then what is the work done by the force on the body​

Answer 1

Answer:

80J

Explanation:

Initial K. E=1/2*10*(5)^2

=125J

Final K. E. =1/2*10*(3)^2

=45J

Work done=80J