Force acting on a particle is 5N. If the unit of length and time are doubled and the unit of mass is halved, the find the numerical value of the force in the new unit.
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Answered by
3
We know the initial values
Given,
F=5N=ma
Initial value
m=m
l=l
t=t
Now new values are
l=2l
t=2t
m=½m
Now,
F=ma
5=ma
5=m×l/t
Now,
F=½m×2l/2t
F=½(m×l/t)
F=½×5
F=2.5N
So new value is this
hazelreeva:
the correct answer is 20N
okay i vl solve it
if the answer is 20 then the question should be changed
yes i agree with u
Answered by
13
F = 5N
F = m×a
F = M × L/T²
length and time are doubled
mass is halved
let the new force = Fₓ
Fₓ = M/2 × 2L/4T²
Fₓ = M × L/4T²
new force(Fₓ) = F/4
Numerical value of new force = 5/4 N
F = m×a
F = M × L/T²
length and time are doubled
mass is halved
let the new force = Fₓ
Fₓ = M/2 × 2L/4T²
Fₓ = M × L/4T²
new force(Fₓ) = F/4
Numerical value of new force = 5/4 N
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